This system call takes one parameter, which is the highest memory address needed to be set. This value is stored in the EBX register.
In case of any error, sys_brk() returns -1 or returns the negative error code itself. The following example demonstrates dynamic memory allocation.
Example
The following program allocates 16kb of memory using the sys_brk() system call −section .text global _start ;must be declared for using gcc _start: ;tell linker entry point mov eax, 45 ;sys_brk xor ebx, ebx int 80h add eax, 16384 ;number of bytes to be reserved mov ebx, eax mov eax, 45 ;sys_brk int 80h cmp eax, 0 jl exit ;exit, if error mov edi, eax ;EDI = highest available address sub edi, 4 ;pointing to the last DWORD mov ecx, 4096 ;number of DWORDs allocated xor eax, eax ;clear eax std ;backward rep stosd ;repete for entire allocated area cld ;put DF flag to normal state mov eax, 4 mov ebx, 1 mov ecx, msg mov edx, len int 80h ;print a message exit: mov eax, 1 xor ebx, ebx int 80h section .data msg db "Allocated 16 kb of memory!", 10 len equ $ - msgWhen the above code is compiled and executed, it produces the following result −
Allocated 16 kb of memory!
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